3.588 \(\int \frac {1}{x^{3/2} (a+b x)^{5/2}} \, dx\)

Optimal. Leaf size=64 \[ -\frac {16 \sqrt {a+b x}}{3 a^3 \sqrt {x}}+\frac {8}{3 a^2 \sqrt {x} \sqrt {a+b x}}+\frac {2}{3 a \sqrt {x} (a+b x)^{3/2}} \]

[Out]

2/3/a/(b*x+a)^(3/2)/x^(1/2)+8/3/a^2/x^(1/2)/(b*x+a)^(1/2)-16/3*(b*x+a)^(1/2)/a^3/x^(1/2)

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Rubi [A]  time = 0.01, antiderivative size = 64, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {45, 37} \[ -\frac {16 \sqrt {a+b x}}{3 a^3 \sqrt {x}}+\frac {8}{3 a^2 \sqrt {x} \sqrt {a+b x}}+\frac {2}{3 a \sqrt {x} (a+b x)^{3/2}} \]

Antiderivative was successfully verified.

[In]

Int[1/(x^(3/2)*(a + b*x)^(5/2)),x]

[Out]

2/(3*a*Sqrt[x]*(a + b*x)^(3/2)) + 8/(3*a^2*Sqrt[x]*Sqrt[a + b*x]) - (16*Sqrt[a + b*x])/(3*a^3*Sqrt[x])

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n +
1))/((b*c - a*d)*(m + 1)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*Simplify[m + n + 2])/((b*c - a*d)*(m + 1)), Int[(a + b*x)^Simplify[m +
1]*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && ILtQ[Simplify[m + n + 2], 0] &&
NeQ[m, -1] &&  !(LtQ[m, -1] && LtQ[n, -1] && (EqQ[a, 0] || (NeQ[c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && (
SumSimplerQ[m, 1] ||  !SumSimplerQ[n, 1])

Rubi steps

\begin {align*} \int \frac {1}{x^{3/2} (a+b x)^{5/2}} \, dx &=\frac {2}{3 a \sqrt {x} (a+b x)^{3/2}}+\frac {4 \int \frac {1}{x^{3/2} (a+b x)^{3/2}} \, dx}{3 a}\\ &=\frac {2}{3 a \sqrt {x} (a+b x)^{3/2}}+\frac {8}{3 a^2 \sqrt {x} \sqrt {a+b x}}+\frac {8 \int \frac {1}{x^{3/2} \sqrt {a+b x}} \, dx}{3 a^2}\\ &=\frac {2}{3 a \sqrt {x} (a+b x)^{3/2}}+\frac {8}{3 a^2 \sqrt {x} \sqrt {a+b x}}-\frac {16 \sqrt {a+b x}}{3 a^3 \sqrt {x}}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 40, normalized size = 0.62 \[ -\frac {2 \left (3 a^2+12 a b x+8 b^2 x^2\right )}{3 a^3 \sqrt {x} (a+b x)^{3/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(x^(3/2)*(a + b*x)^(5/2)),x]

[Out]

(-2*(3*a^2 + 12*a*b*x + 8*b^2*x^2))/(3*a^3*Sqrt[x]*(a + b*x)^(3/2))

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fricas [A]  time = 0.43, size = 58, normalized size = 0.91 \[ -\frac {2 \, {\left (8 \, b^{2} x^{2} + 12 \, a b x + 3 \, a^{2}\right )} \sqrt {b x + a} \sqrt {x}}{3 \, {\left (a^{3} b^{2} x^{3} + 2 \, a^{4} b x^{2} + a^{5} x\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^(3/2)/(b*x+a)^(5/2),x, algorithm="fricas")

[Out]

-2/3*(8*b^2*x^2 + 12*a*b*x + 3*a^2)*sqrt(b*x + a)*sqrt(x)/(a^3*b^2*x^3 + 2*a^4*b*x^2 + a^5*x)

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giac [B]  time = 1.63, size = 159, normalized size = 2.48 \[ -\frac {2 \, \sqrt {b x + a} b^{2}}{\sqrt {{\left (b x + a\right )} b - a b} a^{3} {\left | b \right |}} - \frac {4 \, {\left (3 \, {\left (\sqrt {b x + a} \sqrt {b} - \sqrt {{\left (b x + a\right )} b - a b}\right )}^{4} b^{\frac {5}{2}} + 12 \, a {\left (\sqrt {b x + a} \sqrt {b} - \sqrt {{\left (b x + a\right )} b - a b}\right )}^{2} b^{\frac {7}{2}} + 5 \, a^{2} b^{\frac {9}{2}}\right )}}{3 \, {\left ({\left (\sqrt {b x + a} \sqrt {b} - \sqrt {{\left (b x + a\right )} b - a b}\right )}^{2} + a b\right )}^{3} a^{2} {\left | b \right |}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^(3/2)/(b*x+a)^(5/2),x, algorithm="giac")

[Out]

-2*sqrt(b*x + a)*b^2/(sqrt((b*x + a)*b - a*b)*a^3*abs(b)) - 4/3*(3*(sqrt(b*x + a)*sqrt(b) - sqrt((b*x + a)*b -
a*b))^4*b^(5/2) + 12*a*(sqrt(b*x + a)*sqrt(b) - sqrt((b*x + a)*b - a*b))^2*b^(7/2) + 5*a^2*b^(9/2))/(((sqrt(b
*x + a)*sqrt(b) - sqrt((b*x + a)*b - a*b))^2 + a*b)^3*a^2*abs(b))

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maple [A]  time = 0.01, size = 35, normalized size = 0.55 \[ -\frac {2 \left (8 b^{2} x^{2}+12 a b x +3 a^{2}\right )}{3 \left (b x +a \right )^{\frac {3}{2}} a^{3} \sqrt {x}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^(3/2)/(b*x+a)^(5/2),x)

[Out]

-2/3*(8*b^2*x^2+12*a*b*x+3*a^2)/(b*x+a)^(3/2)/x^(1/2)/a^3

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maxima [A]  time = 1.34, size = 46, normalized size = 0.72 \[ \frac {2 \, {\left (b^{2} - \frac {6 \, {\left (b x + a\right )} b}{x}\right )} x^{\frac {3}{2}}}{3 \, {\left (b x + a\right )}^{\frac {3}{2}} a^{3}} - \frac {2 \, \sqrt {b x + a}}{a^{3} \sqrt {x}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^(3/2)/(b*x+a)^(5/2),x, algorithm="maxima")

[Out]

2/3*(b^2 - 6*(b*x + a)*b/x)*x^(3/2)/((b*x + a)^(3/2)*a^3) - 2*sqrt(b*x + a)/(a^3*sqrt(x))

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mupad [B]  time = 0.42, size = 71, normalized size = 1.11 \[ -\frac {6\,a^2\,\sqrt {a+b\,x}+16\,b^2\,x^2\,\sqrt {a+b\,x}+24\,a\,b\,x\,\sqrt {a+b\,x}}{\sqrt {x}\,\left (x\,\left (6\,a^4\,b+3\,x\,a^3\,b^2\right )+3\,a^5\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^(3/2)*(a + b*x)^(5/2)),x)

[Out]

-(6*a^2*(a + b*x)^(1/2) + 16*b^2*x^2*(a + b*x)^(1/2) + 24*a*b*x*(a + b*x)^(1/2))/(x^(1/2)*(x*(6*a^4*b + 3*a^3*
b^2*x) + 3*a^5))

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sympy [B]  time = 3.97, size = 153, normalized size = 2.39 \[ - \frac {6 a^{2} b^{\frac {9}{2}} \sqrt {\frac {a}{b x} + 1}}{3 a^{5} b^{4} + 6 a^{4} b^{5} x + 3 a^{3} b^{6} x^{2}} - \frac {24 a b^{\frac {11}{2}} x \sqrt {\frac {a}{b x} + 1}}{3 a^{5} b^{4} + 6 a^{4} b^{5} x + 3 a^{3} b^{6} x^{2}} - \frac {16 b^{\frac {13}{2}} x^{2} \sqrt {\frac {a}{b x} + 1}}{3 a^{5} b^{4} + 6 a^{4} b^{5} x + 3 a^{3} b^{6} x^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**(3/2)/(b*x+a)**(5/2),x)

[Out]

-6*a**2*b**(9/2)*sqrt(a/(b*x) + 1)/(3*a**5*b**4 + 6*a**4*b**5*x + 3*a**3*b**6*x**2) - 24*a*b**(11/2)*x*sqrt(a/
(b*x) + 1)/(3*a**5*b**4 + 6*a**4*b**5*x + 3*a**3*b**6*x**2) - 16*b**(13/2)*x**2*sqrt(a/(b*x) + 1)/(3*a**5*b**4
+ 6*a**4*b**5*x + 3*a**3*b**6*x**2)

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